| the Example the fifth: the beekeeper serves more than beer families, than is established by norm of loading. It has not executed a planned target.
The Case the first: the beekeeper works without the assistant. Number of beer families on an apiary, norm of loading, planned targets, quotations of payment of a unit of production and work on care of bees the same, as in an example the third (a case the first). Calculation is similar to this example.
The Beekeeper has not pursued the scheme and has received on 0,28 ts honey from one family of bees, and all on an apiary 33,6 ts (instead of 42. The quantity of the received wax, new sotov and new beer families corresponds to a planned target. Thus, actual earnings of the beekeeper for a year have made:
For honey: 1184 rivers 06 to. (35 rivers 24 to. H 33,6 For wax: 52 rivers of 86 (88 rivers 10 to. H 0,6) For a gain sotov: 42 rivers 24 to. (17,6 to. H 240 pieces) For new families: 17 rivers 60 to. (1 river 76 to. H 10) Only 1296 rivers 76 to.
From this sum 1277 rivers 02 are already paid the beekeeper in the form of monthly wages to., Hence, surcharge for received production will make 19 rivers 74 to. Even under condition of plan default.
Sections
the Case of the second
the Case the third
At norm of loading of 200 beer families
the Assistant to the beekeeper
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