| the Example the fourth: the beekeeper serves more than beer families, than is established by norm of loading. It has exceeded a planned target.
The Case the first: the beekeeper works without the assistant. Number of beer families on an apiary, norms of loading, planned targets, quotations of payment of a unit of production and work on care of bees the same, as in an example the third (a case the first). Calculation is similar to this example.
The Beekeeper has exceeded the plan and has received 45 ts honey, 0,7 ts wax, 290 frameworks with honeycombs and 15 new families of bees. Using calculated in an example the third (a case the first) quotations of payment of production, we will define actual wages for production received within year.
For honey: 1585 rivers 80 to. (35 rivers 24 to. H 45
For wax: 61 rivers 67 to. (88 rivers 10 to. H 0,7
For a gain sotov: 51 rivers 04 to. (17,6 to. H 290 pieces)
For new families: 26 rivers 40 to. (1 river 76 to. H 15)
Only 1724 rivers 91 to.
So, for received production the beekeeper has earned 1724 rivers 91 to. Throughout a year for service of bees 1277 rivers 02 have been paid it to. Hence, in the end of a year for received production to it is due in addition to receive 447 rivers 89 to. (1724 rivers 91 k. - 1277 rivers 02 to.). Besides, the award should be paid for production received over the plan to the beekeeper.
Sections
Service bolshego quantities of beer families
the General earnings
the Case of the second
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